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An aqueous solution containing 0.10 g KI...

An aqueous solution containing 0.10 g `KIO_(3)` (formula weight`=214.0`) was treated with an excess of KI solution the solution was acidified with HCl. The liberated `I_(2)` consumed 45.0 " mL of " thiosulphate solution to decolourise the blue starch-iodine complex. Calculate the molarity of the sodium thosulphate solution.

A

0.0623 M

B

0.0313 M

C

0.126 M

D

0.252 M

Text Solution

Verified by Experts

The correct Answer is:
A
`IO_(3^(-))+5I^(-)+H^(+)rarr2I_(2)+H_(2)O`
`2Na_(2)S_(2)O_(3) +I_(2)rarr 2NaI + Na_(2)S_(4)O_(6)`
Now, Moles of `KIO_(3)=(0.1)/(214)`
So, Moles of `I_(2)=3xx(0.1)/(214)`
Now, Moles of `Na_(2)S_(2)O_(3)=2xx3xx(0.1)/(214)`
`:. MxxV_(L)=2xx3xx(0.1)/(214) " " :. M xx(45)/(1000)=2xx3xx(0.1)/(214)`
Now, Molarity of hypo solution `=2xx3xx(0.1)/(214)xx(1000)/(45)=0.0623` M
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