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Some amount of "20V" H(2)O(2) is mixed w...

Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)` for titration.
The volume of `H_(2)O_(2)` solution is :

A

11.2 mL

B

37.2 mL

C

5.6 mL

D

22.4 mL

Text Solution

Verified by Experts

The correct Answer is:
C
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25 mL of H_(2)O_(2) solution were added to excess of acidified solution of KI . The iodine so liberated required 20 mL of 0.1N Na_(2)S_(2)O_(3) for titration Calculate the strength of H_(2)O_(2) in terms of normalility, percentage and volumes. (b) To a 25 mL H_(2)O_(2) solution, excess of acidified solution of KI was added. The iodine liberated required 20 mL of 0.3N sodium thiosulphate solution. Calculate the volume strength of H_(2)O_(2) solution.

To a 25 mL of H_(2)O_(2) solution, excess of acidified solution of KI was added. The iodine liberated required 20 mL of 0.3 N Na_(2)S_(2)O_(3) solution. Calculate the volume strength of H_(2)O_2 solution. Strategy : Volume strength of H_(2)O_(2) solution is related to its normality by the following relation Volume strength (V)=5.6xx"Normality" (N) where, Normality =((meq)H_(2)O_(2))/V_(mL) According to the law of equivalence (meq)_(Na_(2)S_(2)O_(3))=(meq)_(I_(2))=(meq)_(H_(2)O_(2))