Dichloroacetic acid `(CHCI_2COOH)` is oxidised to `CO_(2),H_(2)O` and `CI_(2)` by 600meq of an oxidising agent. Same amount of ammonia to form ammonium dichloroacetate:

Options

A. 0.0167
B. 0.1
C. 0.3
D. 0.6

Answer

B

Explanation

`eq_(acid)=eq_(base)` (VF=1for both)
`CHCl_(2)CO OH+NH_(3)rarrCHCl_(2)CO ONH_(4)`
From reaction, m.moles of `NH_(3)`=m.moles of dichloroacetic acid = 100
`:. ` Moles of `NH_(3)=(100)/(1000)=0.1`