`HNO_(3)` oxidies `NH_(4)^(+)` ions to nitrogen and itself gets reduced to `NO_(2)`. The moles of `HNO_(3)` required by 1 mole of `(NH_(4))_(2)SO_(4)` is:

Options

A. 4
B. 5
C. 6
D. 2

Answer

C

Explanation

`HNO_(3)+NH_(4)^(+)rarrN_(2)+NO_(2)`
V.F. of `HNO_(3)=(5-4)=1`
V.F. of `NH_(4)^(+)=[0-(-3)]=3`
so molar ratio of `HNO_(3)` and `NH_(4)^(+)` is 3:1.
1 mole `(NH_(4))_(2)SO_(4)` is found to contain 2 mole of `NH_(4)^(+)`
So, required moles of `HNO_(3)` is `3xx2=6` mole.