An aqueous solution of `6.3 g` oxalic acid dihydrate is made up to `250 mL`. The volume of `0.1 N NaOH` required to completely neutralise `10 mL` of this solution is

Options

A. 40 mL
B. 20 mL
C. 10 mL
D. 4 mL

Answer

A

Explanation

(1) Equilivalents of `H_(2)C_(2)O_(4).2H_(2)O` in 10 mL = Equivalents of NaOH
`((6.3)/(126//2)xx(1000)/(25))xx(10)/(1000)=0.1xxV` (in litre)
`:. V=0.04 L = 40 mL.`