Home
Class 12
CHEMISTRY
The normality of orthophosphoric acid ...

The normality of orthophosphoric acid having purity of 70% by weight and specific gravity 1.54 is :

A

11 N

B

22 N

C

33 N

D

44 N

Text Solution

AI Generated Solution

The correct Answer is:
To find the normality of orthophosphoric acid (H₃PO₄) with a purity of 70% by weight and a specific gravity of 1.54, we can follow these steps: ### Step 1: Calculate the density of the orthophosphoric acid solution The specific gravity (SG) of a substance is the ratio of its density to the density of water. Since the specific gravity is given as 1.54, we can calculate the density (ρ) of the solution using the formula: \[ \text{Density (ρ)} = \text{Specific Gravity (SG)} \times \text{Density of Water} \] Assuming the density of water is approximately 1 g/mL, we have: \[ \text{Density (ρ)} = 1.54 \, \text{g/mL} \] ### Step 2: Calculate the mass of orthophosphoric acid in 1 mL of solution The purity of the orthophosphoric acid is given as 70% by weight. This means that in 100 g of the solution, there are 70 g of pure orthophosphoric acid. Therefore, in 1 mL of the solution (which weighs 1.54 g), the mass of orthophosphoric acid can be calculated as follows: \[ \text{Mass of H₃PO₄ in 1 mL} = \text{Purity} \times \text{Density} = 0.70 \times 1.54 \, \text{g} = 1.078 \, \text{g} \] ### Step 3: Calculate the mass of orthophosphoric acid in 1000 mL (1 L) of solution To find the mass of orthophosphoric acid in 1 L of solution, we multiply the mass in 1 mL by 1000: \[ \text{Mass of H₃PO₄ in 1000 mL} = 1.078 \, \text{g/mL} \times 1000 \, \text{mL} = 1078 \, \text{g} \] ### Step 4: Determine the equivalent weight of orthophosphoric acid The equivalent weight (EW) of an acid can be calculated using the formula: \[ \text{Equivalent Weight} = \frac{\text{Molar Mass}}{\text{n-factor}} \] The molar mass of H₃PO₄ is approximately 98 g/mol. The n-factor for orthophosphoric acid, which is a triprotic acid (it can donate 3 protons), is 3. Therefore, the equivalent weight is: \[ \text{Equivalent Weight} = \frac{98 \, \text{g/mol}}{3} = 32.66 \, \text{g/equiv} \] ### Step 5: Calculate the normality of the solution Normality (N) is defined as the number of equivalents of solute per liter of solution. We can calculate normality using the formula: \[ \text{Normality (N)} = \frac{\text{Mass of solute (g)}}{\text{Equivalent Weight (g/equiv)} \times \text{Volume of solution (L)}} \] Substituting the values we have: \[ \text{Normality (N)} = \frac{1078 \, \text{g}}{32.66 \, \text{g/equiv} \times 1 \, \text{L}} \approx 33 \, \text{N} \] ### Final Answer The normality of orthophosphoric acid with a purity of 70% by weight and specific gravity of 1.54 is approximately **33 N**. ---

To find the normality of orthophosphoric acid (H₃PO₄) with a purity of 70% by weight and a specific gravity of 1.54, we can follow these steps: ### Step 1: Calculate the density of the orthophosphoric acid solution The specific gravity (SG) of a substance is the ratio of its density to the density of water. Since the specific gravity is given as 1.54, we can calculate the density (ρ) of the solution using the formula: \[ \text{Density (ρ)} = \text{Specific Gravity (SG)} \times \text{Density of Water} \] ...
Promotional Banner

Topper's Solved these Questions

  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE|Exercise APSP (Part-II)|23 Videos
  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE|Exercise APSP (Part-III)|12 Videos
  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE|Exercise Exercise -3 (JEE(MAIN) Online problems)|10 Videos
  • ELECTROCHEMISRY

    RESONANCE|Exercise Advanced Level Problems|88 Videos
  • FUNDAMENTAL CONCEPT

    RESONANCE|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|40 Videos

Similar Questions

Explore conceptually related problems

The solution of sulphuric acid contains 80% by weight H_(2)SO_(4) . Specific gravity of this solution is 1.71. Its normality is about

Molarity of a given orthophosphoric acid solution is 3M. Its normality is

Molarity of a given orthophosphoric acid solution is 3M. Its normality is

The normality of 10% ( weight // volume ) acetic acid is

RESONANCE-EQUIVALENT CONCEPT & TITRATIONS-APSP (Part-I)
  1. Number of moles of CaO required to remove hardness from 1000 litre wat...

    Text Solution

    |

  2. A 5.0 mL of solution of H(2)O(2) liberates 0.508 g of iodine from acid...

    Text Solution

    |

  3. When hypo solution is added to KMnO(4) solution then

    Text Solution

    |

  4. Which of the following equations is a balanced one?

    Text Solution

    |

  5. 10mL of sulphuric acid solution (specific gravity= 1.84) contains 98% ...

    Text Solution

    |

  6. The equivalent mass of MnSO(4) is half its molecular mass when it is c...

    Text Solution

    |

  7. An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 m...

    Text Solution

    |

  8. In the reaction H(2)O(2)^(18)+O(3) to water + oxygen, radioactivity w...

    Text Solution

    |

  9. 1 mole of how many of the following acids neutralize exactly one mol ...

    Text Solution

    |

  10. Compound CrO5 has structure as shown ltbtgt The oxidation number f...

    Text Solution

    |

  11. The normality of orthophosphoric acid having purity of 70% by weight...

    Text Solution

    |

  12. The normality of mixture obtained by mixing 100 mL of 0.2 M H(2)SO(4) ...

    Text Solution

    |

  13. The reagent commonly used to determine hardness of water titrimetrical...

    Text Solution

    |

  14. 40 mL of 0.05 M solution of sodium sesquicarbonate (Na(2)CO(3).NaHCO(...

    Text Solution

    |

  15. In the following reaction 2MnO(4^(-))+5H(2)O(2)^(18)+6H^(+)rarr2Mn^(2+...

    Text Solution

    |

  16. One gram equimolecular mixture of Na(2)CO(3) and NaHCO(3)is reacted wi...

    Text Solution

    |

  17. Which of the following is not a redox reaction ?

    Text Solution

    |

  18. Equivalent weight of chlorine molecule in the equation is : 3Cl(2)+6...

    Text Solution

    |

  19. Cr(2)O(7)^(2-)overset(H^(+))rarrCr^(3+), Eq. wt. of Cr(2)O(7)^(2-) is ...

    Text Solution

    |

  20. One mole of acidified K(2)Cr(2)O(7) on reaction with excess of KCl wil...

    Text Solution

    |