The normality of mixture obtained by mixing 100 mL of 0.2 M `H_(2)SO_(4)` and 200 mL of 0.2 M HCl is

Options

A. 0.0267
B. `0.2670`
C. `1.0267`
D. `1.1670`

Answer

B

Explanation

Normality of a mixture (N) = `(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))`
Normality `(N_(1))` of `H_(2)SO_(4)`=molarity`xx`basicity =`0.2xx2x=0.4`N
`N_(2)=0.2xx1=0.2N`
`V_(1)=100 mL , V_(2)=200 mL`
`N=(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))=(40+40)/(300)=(80)/(300)=0.2670 N`
Normality of mixture of acid and base (N')
`(N')=(N_(1)V_(1)~N_(2)V_(2))/(V_(1)V_(2))`