10 mL of a `H_(2)SO_(4)` solution is diluted to 100 mL. 25 mL of this diluted solution is mixed with 50 mL of 0.5 N NaOH solution. The resulting solution requires 0.265 g `Na_(2)CO_(3)` for complete neutralization. The normality of original `H_(2)SO_(4)` solution is :

Options

A. 12 N
B. 11 N
C. 3N
D. 0.275 N

Answer

A

Explanation

meq of `H_(2)SO_(4)=` meq of NaOH + meq of `Na_(2)CO_(3)`
`Nxx25=0.5xx50+(0.265)/(106//2)xx10^(3)`
or N=1.2
In original `H_(2)SO_(4)` solution
`N_(1)V_(1)=N_(2)V_(2)`
or `N_(1)xx10=1.2xx100`
or `N_(1)=12 N`