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If amixture of Na(2)CO(3) and NaOH in e...

If amixture of `Na_(2)CO_(3)` and NaOH in equimolar quantities when reacts with 0.1 M HCl in presence of phenolphthalein indicator consumes 30 ml of the acid. What will be the volume (in mL) of 0.15 M `H_(2)SO_(4)` used in the separate titration of same mixture in presence of methyl orange indicator.

Text Solution

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The correct Answer is:
15
In presence of Hph indicator
m. eq. of HCl = m. eq. of `Na_(2)CO_(3)+` m.eq. of NaOH
`30xx0.1=(axx1)+(axx1)`
`:. A=1.5`
In presence of MeOH indicator
m.eq. of `H_(2)SO_(4)`=m.eq. of `Na_(2)CO_(3)` + m. eq. of NaOH
`0.15xx2xxV=(axx2)+(axx1)`
V=15 ml
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Volume of 0.1M""H_(2)SO_(4) required to neutralize 30 mL of 0.2 N""NaOH is

A mixture NaOH+Na_(2)CO_(3) required 25mL of 0.1 M HCl using phenolpththalein as the indicator. However, the same amount of the mixture required 30mL of 0.1M HCl when methyl orange was used as the indicator. The molar ration of NaOH and Na_(2)CO_(3) in the mixture was: