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Hg(5)(IO(6))(2) oxidizes KI to I(2) in a...

`Hg_(5)(IO_(6))_(2)` oxidizes KI to `I_(2)` in acid medium and the other product containing iodine is `K_(2)HgI_(4)` . If the `I_(2)` liberated in the number of moles of `Hg_(5)(IO_(6))_(2)` that have reacted is :

A

`10^(-3)`

B

`10^(-4)`

C

`2.5xx10^(-4)`

D

`2.5xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Eq. of `Hg_(5)(IO_(6))_(2)`=Eq. of `I_(2)`=Eq. of `Na_(2)S_(2)O_(3)`
`:. ` (moles of `Hg_(5)(IO_(6))_(2)`)`xx16=0.004xx1`
`:. ` moles of `Hg_(5)(IO_(6))_(2)=2.5xx10^(-4)`.
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