10 mL of 1 NHCl is mixed with 20 mL of 1`MH_(2)SO_(4)` and 30 mL of 1M NaOH. The resultant solution has:

Options

A. 20 meq of `H^(+)` ions
B. 20 meq of `OH^(-)`
C. 0 meq of `H^(+)` or `OH^(-)`
D. 30 milli moles of `OH^(-)`

Answer

A

Explanation

(A) Explanation : No. of meq of `H^(+)=10xx1+20xx2=50 " " `[`:' H_(2)SO_(4), N=2M`]
No. of meqof `OH^(-)=30xx1=30`
No. of meq of `H^(+)` left unreacted = 50 - 30 = 20 meq
Hence, (A) is correct , (B), (C) and (D) are ruled out.