Consider the redox reaction
`2S_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(ө)`

Options

A. `S_(2)O_(3)^(2-)` gets reduced to `S_(4)O_(6)^(2-)`
B. `S_(2)O_(3)^(2-0)` gets oxidised to `S_(4)O_(6)^(2-)`
C. `I_(2)` gets reduced to `I^(-)`
D. `I_(2)` gets oxidised to `I^(-)`

Answer

B, C

Explanation

S undergoes increase in oxidation number from +2 to +2.5, while I undergoes decrease in oxidation number from 0 to -1.