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P and Q are isomers of dicarboxylic acid...

`P` and `Q` are isomers of dicarboxylic acid `C_(4)H_(4)O_(4)`. Bothdecolorize `Br_(2)//H_(2)O`. On heating, `P` forms the cyclic anhydride. Upon treatment with dilute alkaline `KMnO_(4),P` as well as `Q` could produce one or more than one forms `S,T` and `U`.
Compounds formed from `P` and `Q` are, respectively

A

Optically active S and optically active pair (T, U)

B

Optically inactive S and optically inactive pair (T, U)

C

Optically active pair (T, U) and optically active S

D

Optically inactive pair (T, U) and optically inactive S

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The correct Answer is:
B
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