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The coagulation of 200 mL of a positive ...

The coagulation of `200 mL` of a positive colloid took place when `0.73 g HCl` was added to it without changing the volume much. The flocculation value of `HCl` for the colloid is
a. `36.5` , b. `100` , c. `200` , d. `150`

A

`0.36`

B

`36.5`

C

`100`

D

`150`

Text Solution

Verified by Experts

The correct Answer is:
C
200 mL of the sol require = 0.73 g HCl
`= (0.73)/(36.5) mol = 0.02 mol = 20 m mol.`
So, flocculation value of `HCl = (20m"mole")/(0.2 lit) = 100`
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