Home
Class 11
PHYSICS
Given that v=sqrt((2GM)/(R )). Find log ...

Given that `v=sqrt((2GM)/(R ))`. Find log v.

Text Solution

AI Generated Solution

To find \( \log v \) given that \( v = \sqrt{\frac{2GM}{R}} \), we can follow these steps: ### Step 1: Start with the given equation We have: \[ v = \sqrt{\frac{2GM}{R}} \] ...
Promotional Banner

Topper's Solved these Questions

  • MATHEMATICAL TOOLS

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS (4)|7 Videos

  • MATHEMATICAL TOOLS

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS (5)|16 Videos

  • MATHEMATICAL TOOLS

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS (2)|7 Videos

  • GRAVITATION

    MODERN PUBLICATION|Exercise Chapter Practice Test|15 Videos

  • MECHANICAL PROPERTIES OF FLUIDS

    MODERN PUBLICATION|Exercise Chapter Practise Test|16 Videos

Similar Questions

Explore conceptually related problems

v_(e)=sqrt((2GM)/(R))

Two particles of equal masses m go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is v=sqrt((Gm)/(nR)) . Find the value of n.

A mass is taken to a height R from the surface of earth and then is given horizontal velocity v. The minimum value of v so that mass escapes to infinity is sqrt((GM)/(nR)) . Find the value of n.

The velocity of particle is given by v=sqrt(gx) . Find its acceleration.

Check the dimensional consistency of the following equations : (i) de-Broglie wavelength , lambda=(h)/(mv) (ii) Escape velocity , v=sqrt((2GM)/(R)) .

" The displacement x of a particle at the instant when its velocity v is given by "v=sqrt(3x)+16" .Find its acceleration "

Match the column : A particle at a distance r from the centre of a uniform spherical planet of mass M radius R(lt r) has a velocity v magnitude of which is given in column I. Match trajectory from column II about possible nature of orbit. {:(,"Column I",,"Column II"),((A),0lt V lt sqrt((GM)/(r )),(P),"Straight line"),((B),sqrt((GM)/(r )),(Q),"Circle"),((C ),sqrt((2GM)/(r )),(R ),"Parabola"),((D),v gt sqrt((2GM)/(r )),(S ),"Ellipse"):}

A: If the force of gravitation in inversely proportional to the distance r rather than r^(2) given by Newton , then orbital velocity of the satellite around the earth is independent of r . R : (GMm)/r = (mv^(2))/r so , v = sqrt(GM) hence independent of r .

Make r the subject of the formula V=(pir^(2)h)/(3) . Find r, when V=27 pi cm^(3) and h=4cm.

If mass of earth is M ,radius is R and gravitational constant is G,then work done to take 1kg mass from earth surface to infinity will be (A) sqrt((GM)/(2R)) (B) (GM)/(R)] (C) sqrt((2GM)/(R))]