Differentiate the following :
(iii) `sin(3x^(3)+7)`

Explanation

To differentiate the function \( y = \sin(3x^3 + 7) \), we will use the chain rule. The chain rule states that if you have a composite function \( y = f(g(x)) \), then the derivative \( \frac{dy}{dx} \) is given by:

\[ \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \]

Here, \( f(u) = \sin(u) \) and \( g(x) = 3x^3 + 7 \).

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