If the energy ( E) ,velocity (v) and force (F) be taken as fundamental quantities,then the dimension of mass will be

Options

A. `Fv^(-2)`
B. `Fv^(-1)`
C. `Ev^(-2)`
D. `Ev^(2)`

Answer

C

Explanation

`M= k[E]^(a)[v]^(b)[F]^(c )`
`[M^(a)L^(2a)T^(-2a)][M^(0)L^(b)T^(-b)][M^(c )L^(c )T^(-2c)]`
`[M^(a+c)L^(2a+b+c)T^(-2a-b-2c)]`
`a+c=1, 2a+b+c=0, 2a+b+2c=0`
`a=1, b=-2, c=0`
`M= k[E]^(1)[v]^(-2)`