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If the error in the measurement of radiu...

If the error in the measurement of radius of a sphere in `2%` then the error in the determination of volume of the spahere will be

A

`6%`

B

`8%`

C

`12%`

D

`4%`

Text Solution

Verified by Experts

The correct Answer is:
A
Given error percentage of radius is r= 2%
`(triangleV)/(V)= (3triangle r)/(r )=3xx2%= 6%`.
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