If the dimensions of a physical quantity are given by `M^(a)L^(b)T^(c)`, then the physical quantity will be :

Options

A. Velocity if `a=1, b=0, c= -1`
B. Acceleration if `a=1, b=1, c= -2`
C. Force if `a=0, b= -1, c= -2`
D. Pressure if `a=1, b= -1, c= -2`

Answer

D

Explanation

`P=(F)/(A)=[ML^(-1)T^(-2)] implies [M]^(a)[L]^(b)[T]^(c )`
`a=1, b=-1, c= -2`