Using mass (M), length (L), time (T) and current (A) as fundamental quantities, the dimensions of permeability are :

Options

A. `M^(-1)LT^(-2)A`
B. `ML^(2)T^(-2)A^(-1)`
C. `MLT^(-2)A^(-2)`
D. `MLT^(-1)A^(-1)`

Answer

C

Explanation

`mu to ` permeability, `F=qvB, B=(F)/(qv)`
`B=(mu)/(4pi)xx((Idl)/(r^2))`
`(F)/(qv)=(mu)/(4pi)((AL)/(L^2))`
`[(MLT^(-2))/(AT*LT^(-1))]=mu[(A)/(L)]`
`mu =(ML^(2)T^(-2))/(A^(2)T^(0)L)`
`=[MLT^(-2)A^(-2)]`