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In an experiment four quantities a,b,c a...

In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is

A

`10%`

B

`7%`

C

`4%`

D

`14%`

Text Solution

Verified by Experts

The correct Answer is:
D
`(triangleP)/(P)xx100= pm[3((triangle a)/(a)xx100)+2((triangleb)/(b)xx100)+((trianglec)/(c )xx100)+((triangled)/(d)xx100)]`
`= pm[3xx1%+2xx2%+3%+4%]`
% error in P= 14%
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