The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively without any object, the zero of its circular scale lies 3 divisions below the mean line.
The readings of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is :

Options

A. `5.740 mm`
B. `5.950 mm`
C. `5.725 mm`
D. `5.755 mm`

Answer

D

Explanation

Pitch =0.5 mm
LC `=(0.5)/(100)=0.005mm`
Zero error `= -3xx0.005= -0.015mm`
Actual value = main scale reading +circular scale reading `xx` LC -ZE
`=5.5mm+(48xx0.005)mm+0.-015mm`
`=5.755mm`