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A rotor rotating with an angular speed o...

A rotor rotating with an angular speed of `100rads^(-1)`. To make it rotate with same speed, an engine has to transmit a torque of 200 Nm. Calculate the power of engine.

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To calculate the power of the engine, we can use the relationship between power (P), torque (τ), and angular velocity (ω). The formula is given by: \[ P = τ \cdot ω \] Where: - \( P \) is the power in watts (W), - \( τ \) is the torque in newton-meters (Nm), - \( ω \) is the angular velocity in radians per second (rad/s). ### Step-by-Step Solution: 1. **Identify the given values:** - Torque \( τ = 200 \, \text{Nm} \) - Angular speed \( ω = 100 \, \text{rad/s} \) 2. **Substitute the values into the power formula:** \[ P = τ \cdot ω = 200 \, \text{Nm} \cdot 100 \, \text{rad/s} \] 3. **Calculate the power:** \[ P = 200 \times 100 = 20000 \, \text{W} \] 4. **Convert watts to kilowatts (if necessary):** \[ P = 20000 \, \text{W} = 20 \, \text{kW} \] Thus, the power of the engine is \( 20000 \, \text{W} \) or \( 20 \, \text{kW} \). ### Final Answer: The power of the engine is \( 20000 \, \text{W} \) or \( 20 \, \text{kW} \). ---
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