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A body is projected with a speed 160 m/s...

A body is projected with a speed 160 m/s at an angle `53^(@)` with the horizontal, At the highest point, body explodes into two pieces with mass ratio 1:3. Smaller piece comes to rest immediately after explosion. Find the distance of point from point of projection where heavier piece strikes the horizontal surface.

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To solve the problem step by step, we will follow the procedure outlined in the video transcript. ### Step 1: Identify the given data - Initial speed \( u = 160 \, \text{m/s} \) - Angle of projection \( \theta = 53^\circ \) - Mass ratio of the two pieces after explosion \( m_1:m_2 = 1:3 \) ### Step 2: Calculate the range of the projectile before the explosion ...
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Knowledge Check

  • A body of mass m is projected with intial speed u at an angle theta with the horizontal. The change in momentum of body after time t is :-

    A
    m u `sin theta`
    B
    2 m u `sin theta`
    C
    m g t
    D
    zero

  • A stone is projected with speed of 50 ms^(-1) at an angle of 60^(@) with the horizontal. The speed of the stone at highest point of trajectory is

    A
    `75 ms^(-1)`
    B
    `25ms^(-1)`
    C
    `50 ms^(-1)`
    D
    cannot find

  • A body is projected at an angle of 30^(@) with the horizontal with momentum P .At its highest point the magnitude of the momentum is:

    A
    `sqrt3/2P`
    B
    `2/sqrt3P`
    C
    `P`
    D
    `P/2`