Derive an expression for the moment of inertia of thin uniform rod about an axis passing through its one end. Also find the radius of gyration.

Derive an expression for moment of inertia of a thin circular ring about an axis passing through its centre and perpendicular to the plane of the ring.

Figure shows the variation of the moment of inertia of a uniform rod, about an axis passing through itss centre and inclined at an angle theta to the length. The moment of inertia of the rod about an axis passing through one of its ends and making an angle theta=(pi)/(3) will be

State the expression for the moment of inertia of a thin uniform disc about an axis perpendicular to its plane and through its centre. Hence deduce the expression for its moment of inertia about a tangential axis perpendicular to its plane.

The moment of inertia of a thin uniform rod about an axis passing through its centre and perpendicular to its length is I_(0) . What is the moment of inertia of the rod about an axis passing through one end and perpendicular to the rod ?

Three identical thin rods, each of mass m and length l , are joined to form an equilateral triangular frame. Find the moment of inertia of the frame about an axis parallel to tis one side and passing through the opposite vertex. Also find its radius of gyration about the given axis.

A thin rod of mass M and length L is bent into a circular ring. The expression for moment of inertia of ring about an axis passing through its diameter is

A uniform rod of length 1 metre has a mass of 500 gram . What is moment of inertia of the rod about an axis passing through the centre of the rod perpendicular to its length. How is moment of inertia changed when the same axis passes through one end of the rod ?