The radius of gyration of an uniform rod of length `L` about an axis passing through its centre of mass and perpendicular to its length is.

Options

A. `(l)/(2 sqrt(3))`
B. `(l)/(sqrt(3))`
C. `(2l)/(sqrt(3))`
D. l

Answer

A

Explanation

Moment of inertia of the rod about its centre and perpendicular to the length is `I=(ml^(2))/(12)`. If k is radius of gyration then we can write the following:
`I=(ml^(2))/(12)=mk^(2)impliesk=(1)/(2sqrt3)`