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A ring performs pure rolling on a horizo...

A ring performs pure rolling on a horizontal fixed surface with its centre moving with speed v.

A

Maximum possible speed that any particle of ring may have is `v//sqrt(2)`

B

Minimum possible speed that any particle of ring may have is `v//sqrt(2)`

C

particles on the ring may have speed anywhere between 0 and 2u.

D

None of these

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The correct Answer is:
To solve the problem of a ring performing pure rolling on a horizontal surface with its center moving at speed \( v \), we need to analyze the velocities of different points on the ring. ### Step-by-Step Solution: 1. **Understanding Pure Rolling**: - In pure rolling motion, the point of contact between the ring and the surface is momentarily at rest. This means that the velocity of the center of the ring, \( v \), is equal to the linear velocity of the ring's center. 2. **Identifying the Points on the Ring**: - Consider a ring of radius \( r \). The center of the ring moves with speed \( v \). - The ring has points at the top, bottom, and sides. We will analyze the velocities at these points. 3. **Velocity at the Point of Contact**: - The point of contact with the ground has a velocity of \( 0 \) because it is at rest during pure rolling. 4. **Velocity at the Topmost Point**: - The topmost point of the ring moves forward with the speed of the center plus the speed due to rotation. - The linear speed due to rotation at the topmost point is \( \omega r \), where \( \omega \) is the angular velocity. - For pure rolling, we have the relationship \( v = \omega r \). Thus, the speed at the topmost point is: \[ v_{\text{top}} = v + \omega r = v + v = 2v \] 5. **Velocity at the Bottommost Point**: - The bottommost point of the ring is moving backward with the speed of the center minus the speed due to rotation. - Hence, the speed at the bottommost point is: \[ v_{\text{bottom}} = v - \omega r = v - v = 0 \] 6. **Conclusion on Velocities**: - The velocities of the particles on the ring range from \( 0 \) (at the bottommost point) to \( 2v \) (at the topmost point). - Therefore, the particles on the ring can have speeds anywhere between \( 0 \) to \( 2v \). 7. **Answering the Options**: - Maximum possible speed at any particle of the ring is \( 2v \). - Minimum possible speed at any particle is \( 0 \). - The particles on the ring may have speeds anywhere between \( 0 \) to \( 2v \). ### Final Answer: - The correct option is: "Particle on the ring may have speed anywhere between \( 0 \) to \( 2v \)."

To solve the problem of a ring performing pure rolling on a horizontal surface with its center moving at speed \( v \), we need to analyze the velocities of different points on the ring. ### Step-by-Step Solution: 1. **Understanding Pure Rolling**: - In pure rolling motion, the point of contact between the ring and the surface is momentarily at rest. This means that the velocity of the center of the ring, \( v \), is equal to the linear velocity of the ring's center. 2. **Identifying the Points on the Ring**: ...
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MODERN PUBLICATION-SYSTEMS OF PARTICLES AND ROTATIONAL MOTION-COMPETITION FILE (OBJECTIVE TYPE QUESTIONS (MULTIPLE CHOICE QUESTIONS) (MULTIPLE CHOICE QUESTIONS WITH ONLY ONE CORRECT ANSWER) )
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