The moments of inertia of two rotating bodies A and B are `I_(A)` and `I_(B). (I_(A) gt I_(B))` and their angular momenta are equal. Which one has greater `K.E.` ?

Options

A. K.E. of A=K.E. of B
B. K.E. of A gt K.E. of B
C. K.E. of A `gt` K.E. of B
D. None of these

Explanation

For given angular momentum J, K.E. of the system can be written as `K=(J^(2))/(2I)`
Hence for given angular momentum K.E. is inversely proportional to the moment of inertia. Since moment of inertia A is less than moment of inertia of B hence K.E. of A must be greater than B. Option (b) is correct.