A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination `30^(@)`. The centre of mass of the cylinder has speed of 4 m/s. The distance travelled by the cylinder on the inclined surface will be, [ take `g=10m//s^(2)]`

Options

A. `2.4 m`
B. `2.2m`
C. `1.6 m`
D. `1.2 m`

Answer

A

Explanation

Using energy conservation we can write the following:
`(3)/(4)mv^(2)=mghimpliesh=(3v^(2))/(4g)=(3xx(4)^(2))/(4xx10)=1.2m`

Now, `(3)/(4)mv^(2)=mghimpliesh=(3v^(2))/(4g)=(3xx(4)^(2))/(4xx10)=1.2m`
x=2.4 m
Hence option (a) is correct.