A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity `v m//s`. If it is to climb the inclined surface then `v` should be :

Options

A. `ge sqrt((10gh)/(7))`
B. `ge sqrt(2gh)`
C. `2gh`
D. `(10)/(7)gh`

Answer

A

Explanation

`(1)/(2)Iomega^(2)+(1)/(2)mv^(2)gemgh`
`(1)/(2)xx(2)/(5)mr^(2)((v)/(r))^(2)+(1)/(2)mv^(2)gemgh`
`((1)/(5)mv^(2)+(1)/(2)mv^(2))gemgh`
`(7)/(10)mv^(2)gemgh`
`vgesqrt((10gh)/(7))`