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The two thigh bones (femur bones) each o...

The two thigh bones (femur bones) each of cross-sectional area `10 cm^(2)` support the upper part of a human body of mass 40 kg . Estimate the average pressure sustained by the femurs. `g=10m//s^(2)`

Text Solution

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Given, area of cross section of one femur `= 10 cm^2`
`therefore ` Total cross sectional area of the femurs `A =2 xx 10 cm^2= 20 xx 10^(-4) m^2`
Force is acting vertically downwards and hence, normally on the femurs.
`So, F=mg =40 xx 10=400N`
Average pressure sustained by the femurs,
`P_(av)=F/A=(400)/(20 xx 10^(-4))`
`=2 xx 10^(5) N//m^(2)`
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