A square metal plate of 5 cm side is moving parallel to another plate with a velocity of 10 cm/s. Both the plates are immersed in water. If the viscous force is 300 dyne and viscotity of water is 0.01 poise, then calculate the distance between the paltes.

Explanation

To solve the problem of finding the distance between two parallel plates moving in water, we can follow these steps:

### Step 1: Identify the given data
- Side length of the square plate, \( L = 5 \, \text{cm} \)
- Velocity of the plate, \( v = 10 \, \text{cm/s} \)
- Viscous force, \( F = 300 \, \text{dyne} \)
- Viscosity of water, \( \eta = 0.01 \, \text{poise} \)

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