A capillary tube of length 25 cm and diameter 0.1cm is fitted horizontally to a vessel full of a liquid of coefficient of visocity 0.012 cgs unit. The depth of the capillary tube below the surface of liquid is 15 cm. If the density of liquid is `0.8 g//cm^(3)`, calculate the amount of the liquid that will flow out in 7 minutes. Take `g=980 cm//s^(2)`

Explanation

To solve the problem step by step, we will use the principles of fluid mechanics, particularly the Hagen-Poiseuille equation for flow through a capillary tube.

### Step 1: Gather the Given Data
- Length of the capillary tube, \( L = 25 \, \text{cm} \)
- Diameter of the capillary tube, \( d = 0.1 \, \text{cm} \)
- Radius of the capillary tube, \( r = \frac{d}{2} = 0.05 \, \text{cm} \)
- Coefficient of viscosity, \( \nu = 0.012 \, \text{cgs unit} \)
- Depth of the capillary tube below the surface of the liquid, \( h = 15 \, \text{cm} \)
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