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A liquid of specific gravity 0.8 rises u...

A liquid of specific gravity 0.8 rises up in a capillary tube up to a height of 10 cm, while mercury falls down by 4 cm in the same tube. If the angle of contact between surface of the tube and liquid is zero and it is `135^(@)` for mercury, calculate the ratio of surface tension of mercury and the liquid. Take, specific gravity of mercury `=13.6 cos 135^@=-0.71`

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To solve the problem, we need to calculate the ratio of the surface tension of mercury (T2) to the surface tension of the liquid (T1) based on the given heights of the liquids in a capillary tube and their specific gravities. ### Step-by-Step Solution: 1. **Identify Given Values:** - Specific gravity of the liquid (SG1) = 0.8 - Height of the liquid column (h1) = 10 cm = 0.1 m - Height of the mercury column (h2) = 4 cm = 0.04 m ...
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