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In a hydraulic press, the area of smalle...

In a hydraulic press, the area of smaller and larger pistons are `5 cm^(2) and 20 cm^(2)`, respectively. Calculate the weight which can be raised by larger piston if a force of 100 kgf is applied on smaller piston.

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To solve the problem of calculating the weight that can be raised by the larger piston in a hydraulic press, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Area of smaller piston, \( A_1 = 5 \, \text{cm}^2 \) - Area of larger piston, \( A_2 = 20 \, \text{cm}^2 \) - Force applied on the smaller piston, \( F_1 = 100 \, \text{kgf} \) 2. **Convert the Force to Newtons:** - Since \( 1 \, \text{kgf} \) is equivalent to \( 9.81 \, \text{N} \): \[ F_1 = 100 \, \text{kgf} \times 9.81 \, \text{N/kgf} = 981 \, \text{N} \] 3. **Calculate the Pressure Exerted on the Smaller Piston:** - Pressure \( P \) is defined as force per unit area: \[ P = \frac{F_1}{A_1} \] - Substituting the values: \[ P = \frac{981 \, \text{N}}{5 \, \text{cm}^2} \] - Converting \( 5 \, \text{cm}^2 \) to \( \text{m}^2 \) (since \( 1 \, \text{cm}^2 = 10^{-4} \, \text{m}^2 \)): \[ A_1 = 5 \times 10^{-4} \, \text{m}^2 \] - Therefore, \[ P = \frac{981 \, \text{N}}{5 \times 10^{-4} \, \text{m}^2} = 1962000 \, \text{N/m}^2 \, (\text{Pascals}) \] 4. **Apply Pascal’s Law:** - According to Pascal's law, the pressure in a hydraulic system is the same at all points. Thus, the pressure on the larger piston \( P \) is also given by: \[ P = \frac{F_2}{A_2} \] - Where \( F_2 \) is the force exerted by the larger piston. 5. **Calculate the Force on the Larger Piston:** - Rearranging the equation for \( F_2 \): \[ F_2 = P \times A_2 \] - Substituting the values: \[ A_2 = 20 \, \text{cm}^2 = 20 \times 10^{-4} \, \text{m}^2 \] - Therefore, \[ F_2 = 1962000 \, \text{N/m}^2 \times 20 \times 10^{-4} \, \text{m}^2 = 3920 \, \text{N} \] 6. **Convert the Force on the Larger Piston to kgf:** - To convert \( F_2 \) back to kgf: \[ F_2 \text{ (in kgf)} = \frac{3920 \, \text{N}}{9.81 \, \text{N/kgf}} \approx 400 \, \text{kgf} \] ### Final Answer: The weight that can be raised by the larger piston is approximately **400 kgf**.
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