Iceberg floats in water with part of it submerged. What is the fraction of the volume of iceberg submerged if the density of ice is `rho_i = 0.917 g cm^(-3) ?`

Explanation

Let V be the total volume of the iceberg and V. be its volume submerged inside the water.
Since the iceberg is floating on the water, the weight of the water displaced by the iceberg is equal to the total weight of the iceberg. So, `V.p_(w)g=Vp_(i)g`
Fraction of the volume of iceberg submerged
`(V.)/V=p_(i)/p_(w)=(0.917)/1=0.917`
This implies that 91.7% of the iceberg is below water.