One third of a cylinder of 3 m height is filled with oil of density 0.62 g cm`""^(-3)`. and the rest of it is filled with mercury of density 13.6 g cm`""^(-3)`. Calculate the total pressure at the bottom of cylinder due to both oil and mercury.

Explanation

To solve the problem, we need to calculate the total pressure at the bottom of the cylinder due to both the oil and mercury. We will follow these steps:

### Step 1: Understand the Heights of the Fluids
The total height of the cylinder is 3 m. Since one third of the cylinder is filled with oil, the height of the oil column is:
\[ h_{\text{oil}} = \frac{1}{3} \times 3 \, \text{m} = 1 \, \text{m} \]
The remaining height, which is filled with mercury, is:
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