Calculate the terminal velocity of a water drop of radius 0.002 mm falling in air. Density of air `=1.3" kg/m"^(3)`.
Density of water `=10^3 "kg/m"^(3).` Coefficient of viscosity of air is `1.7 xx 10^(-5)" decapoise."`

Explanation

To calculate the terminal velocity of a water drop falling in air, we can use the formula for terminal velocity \( V_t \) given by:

\[ V_t = \frac{2}{9} \cdot \frac{\eta \cdot r^2 \cdot ( \rho - \rho_a ) \cdot g}{\eta} \]

Where:
- \( \eta \) is the coefficient of viscosity of air,
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