Water is flowing down from a water tap of diameter 1.12 cm at the rate of 2 L/min. Discuss the type of flow - laminar or turbulent. The coefficient of viscosity of water is `10^(-3)` Pas.

Explanation

`D=1.12 xx 10^(-2)m`
`V=2L"/min"=2/(60) xx 10^(-3) m^(3) s^(-1)`
As `V=a v_(c)`
`v_(c)=V/a =(V)/(pi D^(2)//4)`
As Reynold Number `=N_(R)=(pDv_(c))/(eta)`
`=(pDV)/(eta n D^(2)//4)`
`=(4pV)/(eta pi D)`
`=(4 xx 1000 xx 2 xx 10^(-3))/(60 xx 10^(-3) xx 3.14 xx 1.12 xx 10^(-2))`
`=3791 gt 3000`
The flow is turbulent in nature.