A liquid drop of diameter 6 mm breaks into 27 droplets of same size. What will be the change in surface energy if surface tension of liquid drop is `0.06 Nm""^(-1)?`

Explanation

To solve the problem of finding the change in surface energy when a liquid drop breaks into smaller droplets, we can follow these steps:

### Step 1: Determine the radius of the original drop
The diameter of the original drop is given as 6 mm. Therefore, the radius \( R \) of the original drop is:
\[ R = \frac{6 \text{ mm}}{2} = 3 \text{ mm} = 3 \times 10^{-3} \text{ m} \]

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