A capillary tube of radius 0.03 mm is held vertically in a liquid of density `0.85 xx 10^(3)" kg/m"^(3)` and surface tension `4 xx 10^(-2)" N/m"`. The angle of contact of liquid -glass is given by `cosθ = 0.5` then rise of liquid in the capillary tube is.?

Explanation

To find the rise of liquid in a capillary tube, we can use the formula for capillary rise:

\[ h = \frac{2T \cos \theta}{R \rho g} \]

Where:
- \( h \) = height of the liquid column (rise)
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