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A particle is placed at the origin and a...

A particle is placed at the origin and a force F=Kx is acting on it (where k is a positive constant). If `U_((0))=0`, the graph of `U (x)` verses x will be (where U is the potential energy function.)

A

B

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D

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Verified by Experts

The correct Answer is:
D
`F=-(dU)/(dx)=+kx`
`U=int- kxdx= (-kx^(2))/(2)`
`U=-Ax^(2)` it is paraoblic equation
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