A tank with a small hole at the bottom has been filled with water and kerosene (specific gravity 0.8). The height of water is 3 m and that of kerosene 2 m. When the hole is opened the velocity of fluid coming out from it is nearly: `("take g = 10 ms"^(-2)" and density of water "=10^(3)" kg m"^(-3))`

Options

A. `10.7 ms^(-1)`
B. `9.6 ms^(-1)`
C. `8.5 ms^(-1)`
D. `7.6 ms^(-1)`

Answer

B

Explanation

Using Bernoulli.s theorem at the instant of opening of the hole.
`p_("water")+P_("kerosine")=1/2pV_("water")^(2)`
`1000 xx 10 xx 3+800 xx 10 xx 2=1/2 xx 1000V^(2)`
Solving, we get V=9.6m/s