At `0^@C` a thermally isolated container has 200 g of water. When air above water is pumped out, then some of water evaporates and some of it freezes. What will be the mass of ice formed on freezing when there will be no water left in container? Latent heat of vaporisation of water = `2.2 xx 10^6` J/kg and latent heat of fusion of ice = `3.37 xx 10^5` J/kg.

Explanation

To solve the problem, we will use the principle of conservation of energy, which states that the heat lost by the water during evaporation will be equal to the heat gained by the water during freezing.

### Step-by-Step Solution:

1. **Identify the given data:**
- Mass of water, \( m_w = 200 \, \text{g} = 0.2 \, \text{kg} \)
- Latent heat of vaporization of water, \( L_v = 2.2 \times 10^6 \, \text{J/kg} \)
- Latent heat of fusion of ice, \( L_f = 3.37 \times 10^5 \, \text{J/kg} \)
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