A glycerin drop of mass `10^(-3)` g with charge equal to 2e is balanced in an external electric field. Calculate the strength of electric field, if the field is sufficient enough to hold the drop.

Explanation

To solve the problem of finding the strength of the electric field that balances a glycerin drop of mass \(10^{-3}\) g with a charge of \(2e\), we can follow these steps:

### Step 1: Convert the mass of the glycerin drop from grams to kilograms.
The mass \(m\) is given as:
\[ m = 10^{-3} \text{ g} = 10^{-3} \times 10^{-3} \text{ kg} = 10^{-6} \text{ kg} \]

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