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Electric force experienced by a charge o...

Electric force experienced by a charge of `1 muC` is `5 xx 10^(-3)` N. What should be the magnitude of electric field intensity at the position of the charge?

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AI Generated Solution

To find the magnitude of the electric field intensity at the position of the charge, we can use the relationship between electric force, electric field intensity, and charge. The formula is given by: \[ F = E \cdot q \] Where: - \( F \) is the electric force, ...
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The electric force experienced by a charge of 1.0xx10^(-6) C is 1.5 xx 10^(-3) N . Find the magnitude of the electric field at the position of the chaerge.

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Knowledge Check

  • The electric field intensity on the surface of a charged conductor is

    A
    zero
    B
    directed normally to the surface
    C
    directed tangentially to the surface
    D
    directed along `45^(@)` to the surface

  • The electric field intensity on the surface of a charged conductor is

    A
    zero
    B
    directed normally to the surface
    C
    directed tangentially to the surface
    D
    directed along `45^(@)` to the surface

  • A force of 2.25 N acts on a charge of 15xx10^(-4)C . The intensity of electric field at that point is

    A
    `150NC^(-1)`
    B
    `15NC^(-1)`
    C
    `1500NC^(-1)`
    D
    `1.5NC^(-1)`

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