Consider two conductinbg spheres of radill `R_(1) and R_(2)` with `R_(1)gt R_(2).` If the two are at the same potential, and the larger sphere has more charge than the smaller sphere, then

Explanation

The electric potential due to a charged sphere of radius R carrying charge Q is given by:
`V=(Q)/(4pi epsilon_(0)R)`
Let the charge on the spheres with the radii `R_(1)` and `R_(2)` be `Q_(1) and Q_(2)`, respectively .
As potential for both the spheres are same:
`(Q_(1))/(4pi epsilon_(0)R_(1))=(Q_(2))/(4pi epsilon_(0)R_(2)) " " ...(i)`
`rArr (Q_(1))/(Q_(2))=(R_(1))/(R_(2))`
As `R_(1) gt R_(2) rArr Q_(1) gt Q_(2)`
Charge density of spheres are given as
`sigma_(1)=(Q_(1))/(4pi R_(1)^(2)) and sigma_(2)=(Q_(2))/(4pi R_(2)^(2)) " " ...(ii)`
Using (i) and (ii),
`rArr (sigma_(1))/(sigma_(2)) rArr sigma_(1) lt sigma_(2)`
Thus, the charge density of smaller sphere is more than that of the larger one.