We have two metal plates of surface area `1m^(2)` to construct an air parallel plate capacitor. A potential difference of 210 V is to be applied across the capacitor. The dielectric strength of air is 1 and electric field between the plates is `3xx10^(6)V//m`. What can be the minimum separation between two plates? If the capacitor is constructed accordingly then how much charge it will hold when connected across a 210 V supply?

Explanation

To solve the problem step by step, we will first find the minimum separation between the plates of the capacitor and then calculate the charge it can hold when connected to a 210 V supply.

### Step 1: Calculate Minimum Separation Between Plates

The electric field (E) between the plates of a parallel plate capacitor is given by the formula:

\[
E = \frac{V}{d}
...