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Find out equivalent capacitance between A and B. (take each plate Area = A and distance between two conjugative plates is d)

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We can see that there are only two points P and Q between which all the plates are connected. Let us number the surfaces being used as capacitor plates and then rearrange them separately to get the equivalent schematic diagram for the given arrangement.

We can see that three identical capacitors are connected in parallel to each other between points A and B.
`C_(eq)=3C=3 (epsilon_(0)A)/(d)`
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