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A short bar magnet is placed in the magn...

A short bar magnet is placed in the magnetic meridian with its north pole pointing towards geographical south. A neutral point is found at a distance of 30 cm from the centre of the magnet. If the horizontal component of earth's field is 0.4G , calculate the magnetic moment of the magnet .

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AI Generated Solution

To solve the problem, we need to find the magnetic moment of a short bar magnet based on the given parameters. Here's a step-by-step solution: ### Step 1: Understand the Given Data We have the following information: - Distance of the neutral point from the center of the magnet, \( R = 30 \, \text{cm} = 0.3 \, \text{m} \) - Horizontal component of Earth's magnetic field, \( B_H = 0.4 \, \text{G} = 0.4 \times 10^{-4} \, \text{T} \) ### Step 2: Identify the Relevant Formula ...
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A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the centre of the magnet. Calculate the horizontal component of earth’s magnetic field.

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Knowledge Check

  • A short bar magnet of magnetic moment 1.2Am^(2) is placed in the magnetic meridian with its south pole pointing the north. If a neutral point is found at a distance of 20cm from the centre of the magnet, the value of the horizontal component of the earth's magnetic field is

    A
    `3xx10^(-5)T`
    B
    `3xx10^(-4)T`
    C
    `3xx10^(3)T`
    D
    `3xx10^(-2)T`
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